City Q and City R is 567 km apart. Ben left City Q for City R at 9.00 a.m. travelling at an average speed of 63 km/h. Japheth left City Q later than Ben and caught up with him at 1.00 p.m. Japheth was travelling at a speed of 112 km/h.
- At what time did Japheth leave City Q?
- How much later did Ben arrive in City R than Japheth? Express your answer in h as a fraction or mixed number.
(a)
From 9.00 a.m. to 1.00 p.m. = 4 h
Distance that Ben covered when Japheth caught up with Ben
= 4 x 63
= 252 km
Time that Japheth took to travel 252 km
= 252 ÷ 112
= 2
14 h
1 h = 60 min
14 h =
14 x 60 = 15 min
2
14 h = 2 h 15 min
Time that Japheth left City Q:
2 h 15 min before 1.00 p.m. = 10.45 a.m.
(b)
Remaining distance that they had to cover to reach City R
= 567 - 252
= 315 km
Duration that Japheth had to travel before reaching City R
= 315 ÷ 112
= 2
1316 h
Duration that Ben had to travel before reaching City R
= 315 ÷ 63
= 5 h
Duration that Ben took to arrive later than Japheth in City R
= 5 - 2
1316= 2
316 h
Answer(s): (a) 10.45 a.m.; (b) 2
316 h