City Z and City A is 567 km apart. Cody left City Z for City A at 10.00 a.m. travelling at an average speed of 63 km/h. Michael left City Z later than Cody and caught up with him at 2.00 p.m. Michael was travelling at a speed of 108 km/h.

1. At what time did Michael leave City Z?
2. How much later did Cody arrive in City A than Michael? Express your answer in h as a fraction or mixed number.

(a)
From 10.00 a.m. to 2.00 p.m. = 4 h

Distance that Cody covered when Michael caught up with Cody
= 4 x 63
= 252 km

Time that Michael took to travel 252 km
= 252 ÷ 108
= 2¹₃ h

1 h = 60 min
¹₃ h = ¹₃ x 60 = 20 min
2¹₃ h = 2 h 20 min

Time that Michael left City Z:
2 h 20 min before 2.00 p.m. = 11.40 a.m.

(b)
Remaining distance that they had to cover to reach City A
= 567 - 252
= 315 km

Duration that Michael had to travel before reaching City A
= 315 ÷ 108
= 2¹¹₁₂ h

Duration that Cody had to travel before reaching City A
= 315 ÷ 63
= 5 h

Duration that Cody took to arrive later than Michael in City A
= 5 - 2¹¹₁₂
= 2¹₁₂ h

Answer(s): (a) 11.40 a.m.; (b) 2¹₁₂ h