City F and City G is 360 km apart. Tommy left City F for City G at 9.00 a.m. travelling at an average speed of 72 km/h. Asher left City F later than Tommy and caught up with him at 11.00 a.m. Asher was travelling at a speed of 96 km/h.
- At what time did Asher leave City F?
- How much later did Tommy arrive in City G than Asher? Express your answer in h as a fraction or mixed number.
(a)
From 9.00 a.m. to 11.00 a.m. = 2 h
Distance that Tommy covered when Asher caught up with Tommy
= 2 x 72
= 144 km
Time that Asher took to travel 144 km
= 144 ÷ 96
= 1
12 h
1 h = 60 min
12 h =
12 x 60 = 30 min
1
12 h = 1 h 30 min
Time that Asher left City F:
1 h 30 min before 11.00 a.m. = 9.30 a.m.
(b)
Remaining distance that they had to cover to reach City G
= 360 - 144
= 216 km
Duration that Asher had to travel before reaching City G
= 216 ÷ 96
= 2
14 h
Duration that Tommy had to travel before reaching City G
= 216 ÷ 72
= 3 h
Duration that Tommy took to arrive later than Asher in City G
= 3 - 2
14=
34 h
Answer(s): (a) 9.30 a.m.; (b)
34 h