City V and City W is 330 km apart. Wesley left City V for City W at 7.00 a.m. travelling at an average speed of 66 km/h. George left City V later than Wesley and caught up with him at 10.00 a.m. George was travelling at a speed of 72 km/h.
- At what time did George leave City V?
- How much later did Wesley arrive in City W than George? Express your answer in h as a fraction or mixed number.
(a)
From 7.00 a.m. to 10.00 a.m. = 3 h
Distance that Wesley covered when George caught up with Wesley
= 3 x 66
= 198 km
Time that George took to travel 198 km
= 198 ÷ 72
= 2
34 h
1 h = 60 min
34 h =
34 x 60 = 45 min
2
34 h = 2 h 45 min
Time that George left City V:
2 h 45 min before 10.00 a.m. = 7.15 a.m.
(b)
Remaining distance that they had to cover to reach City W
= 330 - 198
= 132 km
Duration that George had to travel before reaching City W
= 132 ÷ 72
= 1
56 h
Duration that Wesley had to travel before reaching City W
= 132 ÷ 66
= 2 h
Duration that Wesley took to arrive later than George in City W
= 2 - 1
56=
16 h
Answer(s): (a) 7.15 a.m.; (b)
16 h
