City D and City E is 476 km apart. Ryan left City D for City E at 10.00 a.m. travelling at an average speed of 68 km/h. Daniel left City D later than Ryan and caught up with him at 12.00 p.m. Daniel was travelling at a speed of 102 km/h.
- At what time did Daniel leave City D?
- How much later did Ryan arrive in City E than Daniel? Express your answer in h as a fraction or mixed number.
(a)
From 10.00 a.m. to 12.00 p.m. = 2 h
Distance that Ryan covered when Daniel caught up with Ryan
= 2 x 68
= 136 km
Time that Daniel took to travel 136 km
= 136 ÷ 102
= 1
13 h
1 h = 60 min
13 h =
13 x 60 = 20 min
1
13 h = 1 h 20 min
Time that Daniel left City D:
1 h 20 min before 12.00 p.m. = 10.40 a.m.
(b)
Remaining distance that they had to cover to reach City E
= 476 - 136
= 340 km
Duration that Daniel had to travel before reaching City E
= 340 ÷ 102
= 3
13 h
Duration that Ryan had to travel before reaching City E
= 340 ÷ 68
= 5 h
Duration that Ryan took to arrive later than Daniel in City E
= 5 - 3
13= 1
23 h
Answer(s): (a) 10.40 a.m.; (b) 1
23 h