City D and City E is 468 km apart. Flynn left City D for City E at 10.00 a.m. travelling at an average speed of 78 km/h. Tom left City D later than Flynn and caught up with him at 2.00 p.m. Tom was travelling at a speed of 117 km/h.
- At what time did Tom leave City D?
- How much later did Flynn arrive in City E than Tom? Express your answer in h as a fraction or mixed number.
(a)
From 10.00 a.m. to 2.00 p.m. = 4 h
Distance that Flynn covered when Tom caught up with Flynn
= 4 x 78
= 312 km
Time that Tom took to travel 312 km
= 312 ÷ 117
= 2
23 h
1 h = 60 min
23 h =
23 x 60 = 40 min
2
23 h = 2 h 40 min
Time that Tom left City D:
2 h 40 min before 2.00 p.m. = 11.20 a.m.
(b)
Remaining distance that they had to cover to reach City E
= 468 - 312
= 156 km
Duration that Tom had to travel before reaching City E
= 156 ÷ 117
= 1
13 h
Duration that Flynn had to travel before reaching City E
= 156 ÷ 78
= 2 h
Duration that Flynn took to arrive later than Tom in City E
= 2 - 1
13=
23 h
Answer(s): (a) 11.20 a.m.; (b)
23 h
