City G and City H is 345 km apart. Zeph left City G for City H at 9.00 a.m. travelling at an average speed of 69 km/h. Will left City G later than Zeph and caught up with him at 12.00 p.m. Will was travelling at a speed of 92 km/h.
- At what time did Will leave City G?
- How much later did Zeph arrive in City H than Will? Express your answer in h as a fraction or mixed number.
(a)
From 9.00 a.m. to 12.00 p.m. = 3 h
Distance that Zeph covered when Will caught up with Zeph
= 3 x 69
= 207 km
Time that Will took to travel 207 km
= 207 ÷ 92
= 2
14 h
1 h = 60 min
14 h =
14 x 60 = 15 min
2
14 h = 2 h 15 min
Time that Will left City G:
2 h 15 min before 12.00 p.m. = 9.45 a.m.
(b)
Remaining distance that they had to cover to reach City H
= 345 - 207
= 138 km
Duration that Will had to travel before reaching City H
= 138 ÷ 92
= 1
12 h
Duration that Zeph had to travel before reaching City H
= 138 ÷ 69
= 2 h
Duration that Zeph took to arrive later than Will in City H
= 2 - 1
12=
12 h
Answer(s): (a) 9.45 a.m.; (b)
12 h
