City M and City N is 560 km apart. Dylan left City M for City N at 7.00 a.m. travelling at an average speed of 70 km/h. George left City M later than Dylan and caught up with him at 10.00 a.m. George was travelling at a speed of 72 km/h.
- At what time did George leave City M?
- How much later did Dylan arrive in City N than George? Express your answer in h as a fraction or mixed number.
(a)
From 7.00 a.m. to 10.00 a.m. = 3 h
Distance that Dylan covered when George caught up with Dylan
= 3 x 70
= 210 km
Time that George took to travel 210 km
= 210 ÷ 72
= 2
1112 h
1 h = 60 min
1112 h =
1112 x 60 = 55 min
2
1112 h = 2 h 55 min
Time that George left City M:
2 h 55 min before 10.00 a.m. = 7.05 a.m.
(b)
Remaining distance that they had to cover to reach City N
= 560 - 210
= 350 km
Duration that George had to travel before reaching City N
= 350 ÷ 72
= 4
3136 h
Duration that Dylan had to travel before reaching City N
= 350 ÷ 70
= 5 h
Duration that Dylan took to arrive later than George in City N
= 5 - 4
3136=
536 h
Answer(s): (a) 7.05 a.m.; (b)
536 h