City W and City X is 520 km apart. Asher left City W for City X at 10.00 a.m. travelling at an average speed of 65 km/h. Jenson left City W later than Asher and caught up with him at 1.00 p.m. Jenson was travelling at a speed of 78 km/h.
- At what time did Jenson leave City W?
- How much later did Asher arrive in City X than Jenson? Express your answer in h as a fraction or mixed number.
(a)
From 10.00 a.m. to 1.00 p.m. = 3 h
Distance that Asher covered when Jenson caught up with Asher
= 3 x 65
= 195 km
Time that Jenson took to travel 195 km
= 195 ÷ 78
= 2
12 h
1 h = 60 min
12 h =
12 x 60 = 30 min
2
12 h = 2 h 30 min
Time that Jenson left City W:
2 h 30 min before 1.00 p.m. = 10.30 a.m.
(b)
Remaining distance that they had to cover to reach City X
= 520 - 195
= 325 km
Duration that Jenson had to travel before reaching City X
= 325 ÷ 78
= 4
16 h
Duration that Asher had to travel before reaching City X
= 325 ÷ 65
= 5 h
Duration that Asher took to arrive later than Jenson in City X
= 5 - 4
16=
56 h
Answer(s): (a) 10.30 a.m.; (b)
56 h
