City Q and City R is 539 km apart. Caden left City Q for City R at 10.00 a.m. travelling at an average speed of 77 km/h. Gabriel left City Q later than Caden and caught up with him at 1.00 p.m. Gabriel was travelling at a speed of 84 km/h.
- At what time did Gabriel leave City Q?
- How much later did Caden arrive in City R than Gabriel? Express your answer in h as a fraction or mixed number.
(a)
From 10.00 a.m. to 1.00 p.m. = 3 h
Distance that Caden covered when Gabriel caught up with Caden
= 3 x 77
= 231 km
Time that Gabriel took to travel 231 km
= 231 ÷ 84
= 2
34 h
1 h = 60 min
34 h =
34 x 60 = 45 min
2
34 h = 2 h 45 min
Time that Gabriel left City Q:
2 h 45 min before 1.00 p.m. = 10.15 a.m.
(b)
Remaining distance that they had to cover to reach City R
= 539 - 231
= 308 km
Duration that Gabriel had to travel before reaching City R
= 308 ÷ 84
= 3
23 h
Duration that Caden had to travel before reaching City R
= 308 ÷ 77
= 4 h
Duration that Caden took to arrive later than Gabriel in City R
= 4 - 3
23=
13 h
Answer(s): (a) 10.15 a.m.; (b)
13 h