City D and City E is 441 km apart. Ian left City D for City E at 7.00 a.m. travelling at an average speed of 63 km/h. Michael left City D later than Ian and caught up with him at 9.00 a.m. Michael was travelling at a speed of 108 km/h.
- At what time did Michael leave City D?
- How much later did Ian arrive in City E than Michael? Express your answer in h as a fraction or mixed number.
(a)
From 7.00 a.m. to 9.00 a.m. = 2 h
Distance that Ian covered when Michael caught up with Ian
= 2 x 63
= 126 km
Time that Michael took to travel 126 km
= 126 ÷ 108
= 1
16 h
1 h = 60 min
16 h =
16 x 60 = 10 min
1
16 h = 1 h 10 min
Time that Michael left City D:
1 h 10 min before 9.00 a.m. = 7.50 a.m.
(b)
Remaining distance that they had to cover to reach City E
= 441 - 126
= 315 km
Duration that Michael had to travel before reaching City E
= 315 ÷ 108
= 2
1112 h
Duration that Ian had to travel before reaching City E
= 315 ÷ 63
= 5 h
Duration that Ian took to arrive later than Michael in City E
= 5 - 2
1112= 2
112 h
Answer(s): (a) 7.50 a.m.; (b) 2
112 h
