City R and City S is 390 km apart. Flynn left City R for City S at 7.00 a.m. travelling at an average speed of 65 km/h. Seth left City R later than Flynn and caught up with him at 10.00 a.m. Seth was travelling at a speed of 90 km/h.
- At what time did Seth leave City R?
- How much later did Flynn arrive in City S than Seth? Express your answer in h as a fraction or mixed number.
(a)
From 7.00 a.m. to 10.00 a.m. = 3 h
Distance that Flynn covered when Seth caught up with Flynn
= 3 x 65
= 195 km
Time that Seth took to travel 195 km
= 195 ÷ 90
= 2
16 h
1 h = 60 min
16 h =
16 x 60 = 10 min
2
16 h = 2 h 10 min
Time that Seth left City R:
2 h 10 min before 10.00 a.m. = 7.50 a.m.
(b)
Remaining distance that they had to cover to reach City S
= 390 - 195
= 195 km
Duration that Seth had to travel before reaching City S
= 195 ÷ 90
= 2
16 h
Duration that Flynn had to travel before reaching City S
= 195 ÷ 65
= 3 h
Duration that Flynn took to arrive later than Seth in City S
= 3 - 2
16=
56 h
Answer(s): (a) 7.50 a.m.; (b)
56 h
