City W and City X is 414 km apart. Jenson left City W for City X at 9.00 a.m. travelling at an average speed of 69 km/h. Peter left City W later than Jenson and caught up with him at 11.00 a.m. Peter was travelling at a speed of 92 km/h.

1. At what time did Peter leave City W?
2. How much later did Jenson arrive in City X than Peter? Express your answer in h as a fraction or mixed number.

(a)
From 9.00 a.m. to 11.00 a.m. = 2 h

Distance that Jenson covered when Peter caught up with Jenson
= 2 x 69
= 138 km

Time that Peter took to travel 138 km
= 138 ÷ 92
= 1¹₂ h

1 h = 60 min
¹₂ h = ¹₂ x 60 = 30 min
1¹₂ h = 1 h 30 min

Time that Peter left City W:
1 h 30 min before 11.00 a.m. = 9.30 a.m.

(b)
Remaining distance that they had to cover to reach City X
= 414 - 138
= 276 km

Duration that Peter had to travel before reaching City X
= 276 ÷ 92
= 3 h

Duration that Jenson had to travel before reaching City X
= 276 ÷ 69
= 4 h

Duration that Jenson took to arrive later than Peter in City X
= 4 - 3
= 1 h

Answer(s): (a) 9.30 a.m.; (b) 1 h