City P and City Q is 560 km apart. Valen left City P for City Q at 11.00 a.m. travelling at an average speed of 80 km/h. John left City P later than Valen and caught up with him at 2.00 p.m. John was travelling at a speed of 90 km/h.
- At what time did John leave City P?
- How much later did Valen arrive in City Q than John? Express your answer in h as a fraction or mixed number.
(a)
From 11.00 a.m. to 2.00 p.m. = 3 h
Distance that Valen covered when John caught up with Valen
= 3 x 80
= 240 km
Time that John took to travel 240 km
= 240 ÷ 90
= 2
23 h
1 h = 60 min
23 h =
23 x 60 = 40 min
2
23 h = 2 h 40 min
Time that John left City P:
2 h 40 min before 2.00 p.m. = 11.20 a.m.
(b)
Remaining distance that they had to cover to reach City Q
= 560 - 240
= 320 km
Duration that John had to travel before reaching City Q
= 320 ÷ 90
= 3
59 h
Duration that Valen had to travel before reaching City Q
= 320 ÷ 80
= 4 h
Duration that Valen took to arrive later than John in City Q
= 4 - 3
59=
49 h
Answer(s): (a) 11.20 a.m.; (b)
49 h
