City Z and City A is 640 km apart. Ian left City Z for City A at 8.00 a.m. travelling at an average speed of 80 km/h. Caden left City Z later than Ian and caught up with him at 11.00 a.m. Caden was travelling at a speed of 96 km/h.
- At what time did Caden leave City Z?
- How much later did Ian arrive in City A than Caden? Express your answer in h as a fraction or mixed number.
(a)
From 8.00 a.m. to 11.00 a.m. = 3 h
Distance that Ian covered when Caden caught up with Ian
= 3 x 80
= 240 km
Time that Caden took to travel 240 km
= 240 ÷ 96
= 2
12 h
1 h = 60 min
12 h =
12 x 60 = 30 min
2
12 h = 2 h 30 min
Time that Caden left City Z:
2 h 30 min before 11.00 a.m. = 8.30 a.m.
(b)
Remaining distance that they had to cover to reach City A
= 640 - 240
= 400 km
Duration that Caden had to travel before reaching City A
= 400 ÷ 96
= 4
16 h
Duration that Ian had to travel before reaching City A
= 400 ÷ 80
= 5 h
Duration that Ian took to arrive later than Caden in City A
= 5 - 4
16=
56 h
Answer(s): (a) 8.30 a.m.; (b)
56 h
