City E and City F is 396 km apart. David left City E for City F at 7.00 a.m. travelling at an average speed of 66 km/h. Eric left City E later than David and caught up with him at 10.00 a.m. Eric was travelling at a speed of 88 km/h.

1. At what time did Eric leave City E?
2. How much later did David arrive in City F than Eric? Express your answer in h as a fraction or mixed number.

(a)
From 7.00 a.m. to 10.00 a.m. = 3 h

Distance that David covered when Eric caught up with David
= 3 x 66
= 198 km

Time that Eric took to travel 198 km
= 198 ÷ 88
= 2¹₄ h

1 h = 60 min
¹₄ h = ¹₄ x 60 = 15 min
2¹₄ h = 2 h 15 min

Time that Eric left City E:
2 h 15 min before 10.00 a.m. = 7.45 a.m.

(b)
Remaining distance that they had to cover to reach City F
= 396 - 198
= 198 km

Duration that Eric had to travel before reaching City F
= 198 ÷ 88
= 2¹₄ h

Duration that David had to travel before reaching City F
= 198 ÷ 66
= 3 h

Duration that David took to arrive later than Eric in City F
= 3 - 2¹₄
= ³₄ h

Answer(s): (a) 7.45 a.m.; (b) ³₄ h