City A and City B is 608 km apart. Ethan left City A for City B at 11.00 a.m. travelling at an average speed of 76 km/h. Liam left City A later than Ethan and caught up with him at 3.00 p.m. Liam was travelling at a speed of 114 km/h.

1. At what time did Liam leave City A?
2. How much later did Ethan arrive in City B than Liam? Express your answer in h as a fraction or mixed number.

(a)
From 11.00 a.m. to 3.00 p.m. = 4 h

Distance that Ethan covered when Liam caught up with Ethan
= 4 x 76
= 304 km

Time that Liam took to travel 304 km
= 304 ÷ 114
= 2²₃ h

1 h = 60 min
²₃ h = ²₃ x 60 = 40 min
2²₃ h = 2 h 40 min

Time that Liam left City A:
2 h 40 min before 3.00 p.m. = 12.20 p.m.

(b)
Remaining distance that they had to cover to reach City B
= 608 - 304
= 304 km

Duration that Liam had to travel before reaching City B
= 304 ÷ 114
= 2²₃ h

Duration that Ethan had to travel before reaching City B
= 304 ÷ 76
= 4 h

Duration that Ethan took to arrive later than Liam in City B
= 4 - 2²₃
= 1¹₃ h

Answer(s): (a) 12.20 p.m.; (b) 1¹₃ h