City T and City U is 520 km apart. George left City T for City U at 10.00 a.m. travelling at an average speed of 65 km/h. Sean left City T later than George and caught up with him at 1.00 p.m. Sean was travelling at a speed of 117 km/h.
- At what time did Sean leave City T?
- How much later did George arrive in City U than Sean? Express your answer in h as a fraction or mixed number.
(a)
From 10.00 a.m. to 1.00 p.m. = 3 h
Distance that George covered when Sean caught up with George
= 3 x 65
= 195 km
Time that Sean took to travel 195 km
= 195 ÷ 117
= 1
23 h
1 h = 60 min
23 h =
23 x 60 = 40 min
1
23 h = 1 h 40 min
Time that Sean left City T:
1 h 40 min before 1.00 p.m. = 11.20 a.m.
(b)
Remaining distance that they had to cover to reach City U
= 520 - 195
= 325 km
Duration that Sean had to travel before reaching City U
= 325 ÷ 117
= 2
79 h
Duration that George had to travel before reaching City U
= 325 ÷ 65
= 5 h
Duration that George took to arrive later than Sean in City U
= 5 - 2
79= 2
29 h
Answer(s): (a) 11.20 a.m.; (b) 2
29 h