City V and City W is 350 km apart. Fabian left City V for City W at 7.00 a.m. travelling at an average speed of 70 km/h. Ahmad left City V later than Fabian and caught up with him at 10.00 a.m. Ahmad was travelling at a speed of 72 km/h.

1. At what time did Ahmad leave City V?
2. How much later did Fabian arrive in City W than Ahmad? Express your answer in h as a fraction or mixed number.

(a)
From 7.00 a.m. to 10.00 a.m. = 3 h

Distance that Fabian covered when Ahmad caught up with Fabian
= 3 x 70
= 210 km

Time that Ahmad took to travel 210 km
= 210 ÷ 72
= 2¹¹₁₂ h

1 h = 60 min
¹¹₁₂ h = ¹¹₁₂ x 60 = 55 min
2¹¹₁₂ h = 2 h 55 min

Time that Ahmad left City V:
2 h 55 min before 10.00 a.m. = 7.05 a.m.

(b)
Remaining distance that they had to cover to reach City W
= 350 - 210
= 140 km

Duration that Ahmad had to travel before reaching City W
= 140 ÷ 72
= 1¹⁷₁₈ h

Duration that Fabian had to travel before reaching City W
= 140 ÷ 70
= 2 h

Duration that Fabian took to arrive later than Ahmad in City W
= 2 - 1¹⁷₁₈
= ¹₁₈ h

Answer(s): (a) 7.05 a.m.; (b) ¹₁₈ h