City M and City N is 420 km apart. Luke left City M for City N at 9.00 a.m. travelling at an average speed of 70 km/h. Will left City M later than Luke and caught up with him at 1.00 p.m. Will was travelling at a speed of 96 km/h.
- At what time did Will leave City M?
- How much later did Luke arrive in City N than Will? Express your answer in h as a fraction or mixed number.
(a)
From 9.00 a.m. to 1.00 p.m. = 4 h
Distance that Luke covered when Will caught up with Luke
= 4 x 70
= 280 km
Time that Will took to travel 280 km
= 280 ÷ 96
= 2
1112 h
1 h = 60 min
1112 h =
1112 x 60 = 55 min
2
1112 h = 2 h 55 min
Time that Will left City M:
2 h 55 min before 1.00 p.m. = 10.05 a.m.
(b)
Remaining distance that they had to cover to reach City N
= 420 - 280
= 140 km
Duration that Will had to travel before reaching City N
= 140 ÷ 96
= 1
1124 h
Duration that Luke had to travel before reaching City N
= 140 ÷ 70
= 2 h
Duration that Luke took to arrive later than Will in City N
= 2 - 1
1124=
1324 h
Answer(s): (a) 10.05 a.m.; (b)
1324 h