City M and City N is 520 km apart. Sean left City M for City N at 9.00 a.m. travelling at an average speed of 65 km/h. Neave left City M later than Sean and caught up with him at 12.00 p.m. Neave was travelling at a speed of 90 km/h.
- At what time did Neave leave City M?
- How much later did Sean arrive in City N than Neave? Express your answer in h as a fraction or mixed number.
(a)
From 9.00 a.m. to 12.00 p.m. = 3 h
Distance that Sean covered when Neave caught up with Sean
= 3 x 65
= 195 km
Time that Neave took to travel 195 km
= 195 ÷ 90
= 2
16 h
1 h = 60 min
16 h =
16 x 60 = 10 min
2
16 h = 2 h 10 min
Time that Neave left City M:
2 h 10 min before 12.00 p.m. = 9.50 a.m.
(b)
Remaining distance that they had to cover to reach City N
= 520 - 195
= 325 km
Duration that Neave had to travel before reaching City N
= 325 ÷ 90
= 3
1118 h
Duration that Sean had to travel before reaching City N
= 325 ÷ 65
= 5 h
Duration that Sean took to arrive later than Neave in City N
= 5 - 3
1118= 1
718 h
Answer(s): (a) 9.50 a.m.; (b) 1
718 h