City V and City W is 490 km apart. Asher left City V for City W at 11.00 a.m. travelling at an average speed of 70 km/h. Wesley left City V later than Asher and caught up with him at 2.00 p.m. Wesley was travelling at a speed of 84 km/h.
- At what time did Wesley leave City V?
- How much later did Asher arrive in City W than Wesley? Express your answer in h as a fraction or mixed number.
(a)
From 11.00 a.m. to 2.00 p.m. = 3 h
Distance that Asher covered when Wesley caught up with Asher
= 3 x 70
= 210 km
Time that Wesley took to travel 210 km
= 210 ÷ 84
= 2
12 h
1 h = 60 min
12 h =
12 x 60 = 30 min
2
12 h = 2 h 30 min
Time that Wesley left City V:
2 h 30 min before 2.00 p.m. = 11.30 a.m.
(b)
Remaining distance that they had to cover to reach City W
= 490 - 210
= 280 km
Duration that Wesley had to travel before reaching City W
= 280 ÷ 84
= 3
13 h
Duration that Asher had to travel before reaching City W
= 280 ÷ 70
= 4 h
Duration that Asher took to arrive later than Wesley in City W
= 4 - 3
13=
23 h
Answer(s): (a) 11.30 a.m.; (b)
23 h