City Y and City Z is 504 km apart. Daniel left City Y for City Z at 11.00 a.m. travelling at an average speed of 63 km/h. Zeph left City Y later than Daniel and caught up with him at 3.00 p.m. Zeph was travelling at a speed of 112 km/h.
- At what time did Zeph leave City Y?
- How much later did Daniel arrive in City Z than Zeph? Express your answer in h as a fraction or mixed number.
(a)
From 11.00 a.m. to 3.00 p.m. = 4 h
Distance that Daniel covered when Zeph caught up with Daniel
= 4 x 63
= 252 km
Time that Zeph took to travel 252 km
= 252 ÷ 112
= 2
14 h
1 h = 60 min
14 h =
14 x 60 = 15 min
2
14 h = 2 h 15 min
Time that Zeph left City Y:
2 h 15 min before 3.00 p.m. = 12.45 p.m.
(b)
Remaining distance that they had to cover to reach City Z
= 504 - 252
= 252 km
Duration that Zeph had to travel before reaching City Z
= 252 ÷ 112
= 2
14 h
Duration that Daniel had to travel before reaching City Z
= 252 ÷ 63
= 4 h
Duration that Daniel took to arrive later than Zeph in City Z
= 4 - 2
14= 1
34 h
Answer(s): (a) 12.45 p.m.; (b) 1
34 h