City N and City P is 528 km apart. Carl left City N for City P at 8.00 a.m. travelling at an average speed of 66 km/h. Tom left City N later than Carl and caught up with him at 11.00 a.m. Tom was travelling at a speed of 108 km/h.
- At what time did Tom leave City N?
- How much later did Carl arrive in City P than Tom? Express your answer in h as a fraction or mixed number.
(a)
From 8.00 a.m. to 11.00 a.m. = 3 h
Distance that Carl covered when Tom caught up with Carl
= 3 x 66
= 198 km
Time that Tom took to travel 198 km
= 198 ÷ 108
= 1
56 h
1 h = 60 min
56 h =
56 x 60 = 50 min
1
56 h = 1 h 50 min
Time that Tom left City N:
1 h 50 min before 11.00 a.m. = 9.10 a.m.
(b)
Remaining distance that they had to cover to reach City P
= 528 - 198
= 330 km
Duration that Tom had to travel before reaching City P
= 330 ÷ 108
= 3
118 h
Duration that Carl had to travel before reaching City P
= 330 ÷ 66
= 5 h
Duration that Carl took to arrive later than Tom in City P
= 5 - 3
118= 1
1718 h
Answer(s): (a) 9.10 a.m.; (b) 1
1718 h