City Z and City A is 330 km apart. Sam left City Z for City A at 10.00 a.m. travelling at an average speed of 66 km/h. Flynn left City Z later than Sam and caught up with him at 1.00 p.m. Flynn was travelling at a speed of 88 km/h.

1. At what time did Flynn leave City Z?
2. How much later did Sam arrive in City A than Flynn? Express your answer in h as a fraction or mixed number.

(a)
From 10.00 a.m. to 1.00 p.m. = 3 h

Distance that Sam covered when Flynn caught up with Sam
= 3 x 66
= 198 km

Time that Flynn took to travel 198 km
= 198 ÷ 88
= 2¹₄ h

1 h = 60 min
¹₄ h = ¹₄ x 60 = 15 min
2¹₄ h = 2 h 15 min

Time that Flynn left City Z:
2 h 15 min before 1.00 p.m. = 10.45 a.m.

(b)
Remaining distance that they had to cover to reach City A
= 330 - 198
= 132 km

Duration that Flynn had to travel before reaching City A
= 132 ÷ 88
= 1¹₂ h

Duration that Sam had to travel before reaching City A
= 132 ÷ 66
= 2 h

Duration that Sam took to arrive later than Flynn in City A
= 2 - 1¹₂
= ¹₂ h

Answer(s): (a) 10.45 a.m.; (b) ¹₂ h