City F and City G is 532 km apart. John left City F for City G at 10.00 a.m. travelling at an average speed of 76 km/h. Lee left City F later than John and caught up with him at 12.00 p.m. Lee was travelling at a speed of 96 km/h.
- At what time did Lee leave City F?
- How much later did John arrive in City G than Lee? Express your answer in h as a fraction or mixed number.
(a)
From 10.00 a.m. to 12.00 p.m. = 2 h
Distance that John covered when Lee caught up with John
= 2 x 76
= 152 km
Time that Lee took to travel 152 km
= 152 ÷ 96
= 1
712 h
1 h = 60 min
712 h =
712 x 60 = 35 min
1
712 h = 1 h 35 min
Time that Lee left City F:
1 h 35 min before 12.00 p.m. = 10.25 a.m.
(b)
Remaining distance that they had to cover to reach City G
= 532 - 152
= 380 km
Duration that Lee had to travel before reaching City G
= 380 ÷ 96
= 3
2324 h
Duration that John had to travel before reaching City G
= 380 ÷ 76
= 5 h
Duration that John took to arrive later than Lee in City G
= 5 - 3
2324= 1
124 h
Answer(s): (a) 10.25 a.m.; (b) 1
124 h