City R and City S is 300 km apart. Ken left City R for City S at 8.00 a.m. travelling at an average speed of 60 km/h. Eric left City R later than Ken and caught up with him at 10.00 a.m. Eric was travelling at a speed of 80 km/h.
- At what time did Eric leave City R?
- How much later did Ken arrive in City S than Eric? Express your answer in h as a fraction or mixed number.
(a)
From 8.00 a.m. to 10.00 a.m. = 2 h
Distance that Ken covered when Eric caught up with Ken
= 2 x 60
= 120 km
Time that Eric took to travel 120 km
= 120 ÷ 80
= 1
12 h
1 h = 60 min
12 h =
12 x 60 = 30 min
1
12 h = 1 h 30 min
Time that Eric left City R:
1 h 30 min before 10.00 a.m. = 8.30 a.m.
(b)
Remaining distance that they had to cover to reach City S
= 300 - 120
= 180 km
Duration that Eric had to travel before reaching City S
= 180 ÷ 80
= 2
14 h
Duration that Ken had to travel before reaching City S
= 180 ÷ 60
= 3 h
Duration that Ken took to arrive later than Eric in City S
= 3 - 2
14=
34 h
Answer(s): (a) 8.30 a.m.; (b)
34 h