City V and City W is 546 km apart. Vaidev left City V for City W at 10.00 a.m. travelling at an average speed of 78 km/h. Jack left City V later than Vaidev and caught up with him at 1.00 p.m. Jack was travelling at a speed of 108 km/h.
- At what time did Jack leave City V?
- How much later did Vaidev arrive in City W than Jack? Express your answer in h as a fraction or mixed number.
(a)
From 10.00 a.m. to 1.00 p.m. = 3 h
Distance that Vaidev covered when Jack caught up with Vaidev
= 3 x 78
= 234 km
Time that Jack took to travel 234 km
= 234 ÷ 108
= 2
16 h
1 h = 60 min
16 h =
16 x 60 = 10 min
2
16 h = 2 h 10 min
Time that Jack left City V:
2 h 10 min before 1.00 p.m. = 10.50 a.m.
(b)
Remaining distance that they had to cover to reach City W
= 546 - 234
= 312 km
Duration that Jack had to travel before reaching City W
= 312 ÷ 108
= 2
89 h
Duration that Vaidev had to travel before reaching City W
= 312 ÷ 78
= 4 h
Duration that Vaidev took to arrive later than Jack in City W
= 4 - 2
89= 1
19 h
Answer(s): (a) 10.50 a.m.; (b) 1
19 h
