City B and City C is 441 km apart. Fabian left City B for City C at 10.00 a.m. travelling at an average speed of 63 km/h. Asher left City B later than Fabian and caught up with him at 1.00 p.m. Asher was travelling at a speed of 81 km/h.

1. At what time did Asher leave City B?
2. How much later did Fabian arrive in City C than Asher? Express your answer in h as a fraction or mixed number.

(a)
From 10.00 a.m. to 1.00 p.m. = 3 h

Distance that Fabian covered when Asher caught up with Fabian
= 3 x 63
= 189 km

Time that Asher took to travel 189 km
= 189 ÷ 81
= 2¹₃ h

1 h = 60 min
¹₃ h = ¹₃ x 60 = 20 min
2¹₃ h = 2 h 20 min

Time that Asher left City B:
2 h 20 min before 1.00 p.m. = 10.40 a.m.

(b)
Remaining distance that they had to cover to reach City C
= 441 - 189
= 252 km

Duration that Asher had to travel before reaching City C
= 252 ÷ 81
= 3¹₉ h

Duration that Fabian had to travel before reaching City C
= 252 ÷ 63
= 4 h

Duration that Fabian took to arrive later than Asher in City C
= 4 - 3¹₉
= ⁸₉ h

Answer(s): (a) 10.40 a.m.; (b) ⁸₉ h