City J and City K is 312 km apart. Simon left City J for City K at 11.00 a.m. travelling at an average speed of 78 km/h. Cody left City J later than Simon and caught up with him at 1.00 p.m. Cody was travelling at a speed of 104 km/h.
- At what time did Cody leave City J?
- How much later did Simon arrive in City K than Cody? Express your answer in h as a fraction or mixed number.
(a)
From 11.00 a.m. to 1.00 p.m. = 2 h
Distance that Simon covered when Cody caught up with Simon
= 2 x 78
= 156 km
Time that Cody took to travel 156 km
= 156 ÷ 104
= 1
12 h
1 h = 60 min
12 h =
12 x 60 = 30 min
1
12 h = 1 h 30 min
Time that Cody left City J:
1 h 30 min before 1.00 p.m. = 11.30 a.m.
(b)
Remaining distance that they had to cover to reach City K
= 312 - 156
= 156 km
Duration that Cody had to travel before reaching City K
= 156 ÷ 104
= 1
12 h
Duration that Simon had to travel before reaching City K
= 156 ÷ 78
= 2 h
Duration that Simon took to arrive later than Cody in City K
= 2 - 1
12=
12 h
Answer(s): (a) 11.30 a.m.; (b)
12 h
