City T and City U is 385 km apart. Jenson left City T for City U at 7.00 a.m. travelling at an average speed of 77 km/h. Fabian left City T later than Jenson and caught up with him at 10.00 a.m. Fabian was travelling at a speed of 84 km/h.
- At what time did Fabian leave City T?
- How much later did Jenson arrive in City U than Fabian? Express your answer in h as a fraction or mixed number.
(a)
From 7.00 a.m. to 10.00 a.m. = 3 h
Distance that Jenson covered when Fabian caught up with Jenson
= 3 x 77
= 231 km
Time that Fabian took to travel 231 km
= 231 ÷ 84
= 2
34 h
1 h = 60 min
34 h =
34 x 60 = 45 min
2
34 h = 2 h 45 min
Time that Fabian left City T:
2 h 45 min before 10.00 a.m. = 7.15 a.m.
(b)
Remaining distance that they had to cover to reach City U
= 385 - 231
= 154 km
Duration that Fabian had to travel before reaching City U
= 154 ÷ 84
= 1
56 h
Duration that Jenson had to travel before reaching City U
= 154 ÷ 77
= 2 h
Duration that Jenson took to arrive later than Fabian in City U
= 2 - 1
56=
16 h
Answer(s): (a) 7.15 a.m.; (b)
16 h
