City B and City C is 444 km apart. Cole left City B for City C at 7.00 a.m. travelling at an average speed of 74 km/h. Warren left City B later than Cole and caught up with him at 11.00 a.m. Warren was travelling at a speed of 111 km/h.

1. At what time did Warren leave City B?
2. How much later did Cole arrive in City C than Warren? Express your answer in h as a fraction or mixed number.

(a)
From 7.00 a.m. to 11.00 a.m. = 4 h

Distance that Cole covered when Warren caught up with Cole
= 4 x 74
= 296 km

Time that Warren took to travel 296 km
= 296 ÷ 111
= 2²₃ h

1 h = 60 min
²₃ h = ²₃ x 60 = 40 min
2²₃ h = 2 h 40 min

Time that Warren left City B:
2 h 40 min before 11.00 a.m. = 8.20 a.m.

(b)
Remaining distance that they had to cover to reach City C
= 444 - 296
= 148 km

Duration that Warren had to travel before reaching City C
= 148 ÷ 111
= 1¹₃ h

Duration that Cole had to travel before reaching City C
= 148 ÷ 74
= 2 h

Duration that Cole took to arrive later than Warren in City C
= 2 - 1¹₃
= ²₃ h

Answer(s): (a) 8.20 a.m.; (b) ²₃ h