City Z and City A is 441 km apart. Carl left City Z for City A at 10.00 a.m. travelling at an average speed of 63 km/h. Neave left City Z later than Carl and caught up with him at 2.00 p.m. Neave was travelling at a speed of 112 km/h.

1. At what time did Neave leave City Z?
2. How much later did Carl arrive in City A than Neave? Express your answer in h as a fraction or mixed number.

(a)
From 10.00 a.m. to 2.00 p.m. = 4 h

Distance that Carl covered when Neave caught up with Carl
= 4 x 63
= 252 km

Time that Neave took to travel 252 km
= 252 ÷ 112
= 2¹₄ h

1 h = 60 min
¹₄ h = ¹₄ x 60 = 15 min
2¹₄ h = 2 h 15 min

Time that Neave left City Z:
2 h 15 min before 2.00 p.m. = 11.45 a.m.

(b)
Remaining distance that they had to cover to reach City A
= 441 - 252
= 189 km

Duration that Neave had to travel before reaching City A
= 189 ÷ 112
= 1¹¹₁₆ h

Duration that Carl had to travel before reaching City A
= 189 ÷ 63
= 3 h

Duration that Carl took to arrive later than Neave in City A
= 3 - 1¹¹₁₆
= 1⁵₁₆ h

Answer(s): (a) 11.45 a.m.; (b) 1⁵₁₆ h