City J and City K is 480 km apart. Wesley left City J for City K at 7.00 a.m. travelling at an average speed of 60 km/h. Rael left City J later than Wesley and caught up with him at 10.00 a.m. Rael was travelling at a speed of 108 km/h.
- At what time did Rael leave City J?
- How much later did Wesley arrive in City K than Rael? Express your answer in h as a fraction or mixed number.
(a)
From 7.00 a.m. to 10.00 a.m. = 3 h
Distance that Wesley covered when Rael caught up with Wesley
= 3 x 60
= 180 km
Time that Rael took to travel 180 km
= 180 ÷ 108
= 1
23 h
1 h = 60 min
23 h =
23 x 60 = 40 min
1
23 h = 1 h 40 min
Time that Rael left City J:
1 h 40 min before 10.00 a.m. = 8.20 a.m.
(b)
Remaining distance that they had to cover to reach City K
= 480 - 180
= 300 km
Duration that Rael had to travel before reaching City K
= 300 ÷ 108
= 2
79 h
Duration that Wesley had to travel before reaching City K
= 300 ÷ 60
= 5 h
Duration that Wesley took to arrive later than Rael in City K
= 5 - 2
79= 2
29 h
Answer(s): (a) 8.20 a.m.; (b) 2
29 h