City G and City H is 540 km apart. Rael left City G for City H at 10.00 a.m. travelling at an average speed of 60 km/h. Will left City G later than Rael and caught up with him at 2.00 p.m. Will was travelling at a speed of 96 km/h.
- At what time did Will leave City G?
- How much later did Rael arrive in City H than Will? Express your answer in h as a fraction or mixed number.
(a)
From 10.00 a.m. to 2.00 p.m. = 4 h
Distance that Rael covered when Will caught up with Rael
= 4 x 60
= 240 km
Time that Will took to travel 240 km
= 240 ÷ 96
= 2
12 h
1 h = 60 min
12 h =
12 x 60 = 30 min
2
12 h = 2 h 30 min
Time that Will left City G:
2 h 30 min before 2.00 p.m. = 11.30 a.m.
(b)
Remaining distance that they had to cover to reach City H
= 540 - 240
= 300 km
Duration that Will had to travel before reaching City H
= 300 ÷ 96
= 3
18 h
Duration that Rael had to travel before reaching City H
= 300 ÷ 60
= 5 h
Duration that Rael took to arrive later than Will in City H
= 5 - 3
18= 1
78 h
Answer(s): (a) 11.30 a.m.; (b) 1
78 h
