City J and City K is 378 km apart. Billy left City J for City K at 10.00 a.m. travelling at an average speed of 63 km/h. Zane left City J later than Billy and caught up with him at 12.00 p.m. Zane was travelling at a speed of 108 km/h.
- At what time did Zane leave City J?
- How much later did Billy arrive in City K than Zane? Express your answer in h as a fraction or mixed number.
(a)
From 10.00 a.m. to 12.00 p.m. = 2 h
Distance that Billy covered when Zane caught up with Billy
= 2 x 63
= 126 km
Time that Zane took to travel 126 km
= 126 ÷ 108
= 1
16 h
1 h = 60 min
16 h =
16 x 60 = 10 min
1
16 h = 1 h 10 min
Time that Zane left City J:
1 h 10 min before 12.00 p.m. = 10.50 a.m.
(b)
Remaining distance that they had to cover to reach City K
= 378 - 126
= 252 km
Duration that Zane had to travel before reaching City K
= 252 ÷ 108
= 2
13 h
Duration that Billy had to travel before reaching City K
= 252 ÷ 63
= 4 h
Duration that Billy took to arrive later than Zane in City K
= 4 - 2
13= 1
23 h
Answer(s): (a) 10.50 a.m.; (b) 1
23 h
