City E and City F is 666 km apart. Daniel left City E for City F at 10.00 a.m. travelling at an average speed of 74 km/h. Bryan left City E later than Daniel and caught up with him at 2.00 p.m. Bryan was travelling at a speed of 111 km/h.

1. At what time did Bryan leave City E?
2. How much later did Daniel arrive in City F than Bryan? Express your answer in h as a fraction or mixed number.

(a)
From 10.00 a.m. to 2.00 p.m. = 4 h

Distance that Daniel covered when Bryan caught up with Daniel
= 4 x 74
= 296 km

Time that Bryan took to travel 296 km
= 296 ÷ 111
= 2²₃ h

1 h = 60 min
²₃ h = ²₃ x 60 = 40 min
2²₃ h = 2 h 40 min

Time that Bryan left City E:
2 h 40 min before 2.00 p.m. = 11.20 a.m.

(b)
Remaining distance that they had to cover to reach City F
= 666 - 296
= 370 km

Duration that Bryan had to travel before reaching City F
= 370 ÷ 111
= 3¹₃ h

Duration that Daniel had to travel before reaching City F
= 370 ÷ 74
= 5 h

Duration that Daniel took to arrive later than Bryan in City F
= 5 - 3¹₃
= 1²₃ h

Answer(s): (a) 11.20 a.m.; (b) 1²₃ h