City B and City C is 378 km apart. Valen left City B for City C at 10.00 a.m. travelling at an average speed of 63 km/h. John left City B later than Valen and caught up with him at 2.00 p.m. John was travelling at a speed of 108 km/h.
- At what time did John leave City B?
- How much later did Valen arrive in City C than John? Express your answer in h as a fraction or mixed number.
(a)
From 10.00 a.m. to 2.00 p.m. = 4 h
Distance that Valen covered when John caught up with Valen
= 4 x 63
= 252 km
Time that John took to travel 252 km
= 252 ÷ 108
= 2
13 h
1 h = 60 min
13 h =
13 x 60 = 20 min
2
13 h = 2 h 20 min
Time that John left City B:
2 h 20 min before 2.00 p.m. = 11.40 a.m.
(b)
Remaining distance that they had to cover to reach City C
= 378 - 252
= 126 km
Duration that John had to travel before reaching City C
= 126 ÷ 108
= 1
16 h
Duration that Valen had to travel before reaching City C
= 126 ÷ 63
= 2 h
Duration that Valen took to arrive later than John in City C
= 2 - 1
16=
56 h
Answer(s): (a) 11.40 a.m.; (b)
56 h
