City D and City E is 304 km apart. Elijah left City D for City E at 7.00 a.m. travelling at an average speed of 76 km/h. Dylan left City D later than Elijah and caught up with him at 9.00 a.m. Dylan was travelling at a speed of 114 km/h.
- At what time did Dylan leave City D?
- How much later did Elijah arrive in City E than Dylan? Express your answer in h as a fraction or mixed number.
(a)
From 7.00 a.m. to 9.00 a.m. = 2 h
Distance that Elijah covered when Dylan caught up with Elijah
= 2 x 76
= 152 km
Time that Dylan took to travel 152 km
= 152 ÷ 114
= 1
13 h
1 h = 60 min
13 h =
13 x 60 = 20 min
1
13 h = 1 h 20 min
Time that Dylan left City D:
1 h 20 min before 9.00 a.m. = 7.40 a.m.
(b)
Remaining distance that they had to cover to reach City E
= 304 - 152
= 152 km
Duration that Dylan had to travel before reaching City E
= 152 ÷ 114
= 1
13 h
Duration that Elijah had to travel before reaching City E
= 152 ÷ 76
= 2 h
Duration that Elijah took to arrive later than Dylan in City E
= 2 - 1
13=
23 h
Answer(s): (a) 7.40 a.m.; (b)
23 h