City P and City Q is 384 km apart. Eric left City P for City Q at 8.00 a.m. travelling at an average speed of 64 km/h. Fabian left City P later than Eric and caught up with him at 10.00 a.m. Fabian was travelling at a speed of 96 km/h.

1. At what time did Fabian leave City P?
2. How much later did Eric arrive in City Q than Fabian? Express your answer in h as a fraction or mixed number.

(a)
From 8.00 a.m. to 10.00 a.m. = 2 h

Distance that Eric covered when Fabian caught up with Eric
= 2 x 64
= 128 km

Time that Fabian took to travel 128 km
= 128 ÷ 96
= 1¹₃ h

1 h = 60 min
¹₃ h = ¹₃ x 60 = 20 min
1¹₃ h = 1 h 20 min

Time that Fabian left City P:
1 h 20 min before 10.00 a.m. = 8.40 a.m.

(b)
Remaining distance that they had to cover to reach City Q
= 384 - 128
= 256 km

Duration that Fabian had to travel before reaching City Q
= 256 ÷ 96
= 2²₃ h

Duration that Eric had to travel before reaching City Q
= 256 ÷ 64
= 4 h

Duration that Eric took to arrive later than Fabian in City Q
= 4 - 2²₃
= 1¹₃ h

Answer(s): (a) 8.40 a.m.; (b) 1¹₃ h