City V and City W is 546 km apart. Ian left City V for City W at 9.00 a.m. travelling at an average speed of 78 km/h. Pierre left City V later than Ian and caught up with him at 12.00 p.m. Pierre was travelling at a speed of 108 km/h.
- At what time did Pierre leave City V?
- How much later did Ian arrive in City W than Pierre? Express your answer in h as a fraction or mixed number.
(a)
From 9.00 a.m. to 12.00 p.m. = 3 h
Distance that Ian covered when Pierre caught up with Ian
= 3 x 78
= 234 km
Time that Pierre took to travel 234 km
= 234 ÷ 108
= 2
16 h
1 h = 60 min
16 h =
16 x 60 = 10 min
2
16 h = 2 h 10 min
Time that Pierre left City V:
2 h 10 min before 12.00 p.m. = 9.50 a.m.
(b)
Remaining distance that they had to cover to reach City W
= 546 - 234
= 312 km
Duration that Pierre had to travel before reaching City W
= 312 ÷ 108
= 2
89 h
Duration that Ian had to travel before reaching City W
= 312 ÷ 78
= 4 h
Duration that Ian took to arrive later than Pierre in City W
= 4 - 2
89= 1
19 h
Answer(s): (a) 9.50 a.m.; (b) 1
19 h
