City V and City W is 434 km apart. Ben left City V for City W at 8.00 a.m. travelling at an average speed of 62 km/h. Japheth left City V later than Ben and caught up with him at 12.00 p.m. Japheth was travelling at a speed of 96 km/h.

1. At what time did Japheth leave City V?
2. How much later did Ben arrive in City W than Japheth? Express your answer in h as a fraction or mixed number.

(a)
From 8.00 a.m. to 12.00 p.m. = 4 h

Distance that Ben covered when Japheth caught up with Ben
= 4 x 62
= 248 km

Time that Japheth took to travel 248 km
= 248 ÷ 96
= 2⁷₁₂ h

1 h = 60 min
⁷₁₂ h = ⁷₁₂ x 60 = 35 min
2⁷₁₂ h = 2 h 35 min

Time that Japheth left City V:
2 h 35 min before 12.00 p.m. = 9.25 a.m.

(b)
Remaining distance that they had to cover to reach City W
= 434 - 248
= 186 km

Duration that Japheth had to travel before reaching City W
= 186 ÷ 96
= 1¹⁵₁₆ h

Duration that Ben had to travel before reaching City W
= 186 ÷ 62
= 3 h

Duration that Ben took to arrive later than Japheth in City W
= 3 - 1¹⁵₁₆
= 1¹₁₆ h

Answer(s): (a) 9.25 a.m.; (b) 1¹₁₆ h