City U and City V is 325 km apart. Oliver left City U for City V at 8.00 a.m. travelling at an average speed of 65 km/h. Fred left City U later than Oliver and caught up with him at 11.00 a.m. Fred was travelling at a speed of 90 km/h.
- At what time did Fred leave City U?
- How much later did Oliver arrive in City V than Fred? Express your answer in h as a fraction or mixed number.
(a)
From 8.00 a.m. to 11.00 a.m. = 3 h
Distance that Oliver covered when Fred caught up with Oliver
= 3 x 65
= 195 km
Time that Fred took to travel 195 km
= 195 ÷ 90
= 2
16 h
1 h = 60 min
16 h =
16 x 60 = 10 min
2
16 h = 2 h 10 min
Time that Fred left City U:
2 h 10 min before 11.00 a.m. = 8.50 a.m.
(b)
Remaining distance that they had to cover to reach City V
= 325 - 195
= 130 km
Duration that Fred had to travel before reaching City V
= 130 ÷ 90
= 1
49 h
Duration that Oliver had to travel before reaching City V
= 130 ÷ 65
= 2 h
Duration that Oliver took to arrive later than Fred in City V
= 2 - 1
49=
59 h
Answer(s): (a) 8.50 a.m.; (b)
59 h
