City J and City K is 264 km apart. Billy left City J for City K at 11.00 a.m. travelling at an average speed of 66 km/h. Caden left City J later than Billy and caught up with him at 1.00 p.m. Caden was travelling at a speed of 72 km/h.
- At what time did Caden leave City J?
- How much later did Billy arrive in City K than Caden? Express your answer in h as a fraction or mixed number.
(a)
From 11.00 a.m. to 1.00 p.m. = 2 h
Distance that Billy covered when Caden caught up with Billy
= 2 x 66
= 132 km
Time that Caden took to travel 132 km
= 132 ÷ 72
= 1
56 h
1 h = 60 min
56 h =
56 x 60 = 50 min
1
56 h = 1 h 50 min
Time that Caden left City J:
1 h 50 min before 1.00 p.m. = 11.10 a.m.
(b)
Remaining distance that they had to cover to reach City K
= 264 - 132
= 132 km
Duration that Caden had to travel before reaching City K
= 132 ÷ 72
= 1
56 h
Duration that Billy had to travel before reaching City K
= 132 ÷ 66
= 2 h
Duration that Billy took to arrive later than Caden in City K
= 2 - 1
56=
16 h
Answer(s): (a) 11.10 a.m.; (b)
16 h
