City V and City W is 666 km apart. Perry left City V for City W at 9.00 a.m. travelling at an average speed of 74 km/h. Tommy left City V later than Perry and caught up with him at 1.00 p.m. Tommy was travelling at a speed of 111 km/h.
- At what time did Tommy leave City V?
- How much later did Perry arrive in City W than Tommy? Express your answer in h as a fraction or mixed number.
(a)
From 9.00 a.m. to 1.00 p.m. = 4 h
Distance that Perry covered when Tommy caught up with Perry
= 4 x 74
= 296 km
Time that Tommy took to travel 296 km
= 296 ÷ 111
= 2
23 h
1 h = 60 min
23 h =
23 x 60 = 40 min
2
23 h = 2 h 40 min
Time that Tommy left City V:
2 h 40 min before 1.00 p.m. = 10.20 a.m.
(b)
Remaining distance that they had to cover to reach City W
= 666 - 296
= 370 km
Duration that Tommy had to travel before reaching City W
= 370 ÷ 111
= 3
13 h
Duration that Perry had to travel before reaching City W
= 370 ÷ 74
= 5 h
Duration that Perry took to arrive later than Tommy in City W
= 5 - 3
13= 1
23 h
Answer(s): (a) 10.20 a.m.; (b) 1
23 h