City X and City Y is 252 km apart. Ahmad left City X for City Y at 10.00 a.m. travelling at an average speed of 63 km/h. Daniel left City X later than Ahmad and caught up with him at 12.00 p.m. Daniel was travelling at a speed of 108 km/h.
- At what time did Daniel leave City X?
- How much later did Ahmad arrive in City Y than Daniel? Express your answer in h as a fraction or mixed number.
(a)
From 10.00 a.m. to 12.00 p.m. = 2 h
Distance that Ahmad covered when Daniel caught up with Ahmad
= 2 x 63
= 126 km
Time that Daniel took to travel 126 km
= 126 ÷ 108
= 1
16 h
1 h = 60 min
16 h =
16 x 60 = 10 min
1
16 h = 1 h 10 min
Time that Daniel left City X:
1 h 10 min before 12.00 p.m. = 10.50 a.m.
(b)
Remaining distance that they had to cover to reach City Y
= 252 - 126
= 126 km
Duration that Daniel had to travel before reaching City Y
= 126 ÷ 108
= 1
16 h
Duration that Ahmad had to travel before reaching City Y
= 126 ÷ 63
= 2 h
Duration that Ahmad took to arrive later than Daniel in City Y
= 2 - 1
16=
56 h
Answer(s): (a) 10.50 a.m.; (b)
56 h
