City F and City G is 340 km apart. Albert left City F for City G at 10.00 a.m. travelling at an average speed of 68 km/h. Tom left City F later than Albert and caught up with him at 12.00 p.m. Tom was travelling at a speed of 102 km/h.

1. At what time did Tom leave City F?
2. How much later did Albert arrive in City G than Tom? Express your answer in h as a fraction or mixed number.

(a)
From 10.00 a.m. to 12.00 p.m. = 2 h

Distance that Albert covered when Tom caught up with Albert
= 2 x 68
= 136 km

Time that Tom took to travel 136 km
= 136 ÷ 102
= 1¹₃ h

1 h = 60 min
¹₃ h = ¹₃ x 60 = 20 min
1¹₃ h = 1 h 20 min

Time that Tom left City F:
1 h 20 min before 12.00 p.m. = 10.40 a.m.

(b)
Remaining distance that they had to cover to reach City G
= 340 - 136
= 204 km

Duration that Tom had to travel before reaching City G
= 204 ÷ 102
= 2 h

Duration that Albert had to travel before reaching City G
= 204 ÷ 68
= 3 h

Duration that Albert took to arrive later than Tom in City G
= 3 - 2
= 1 h

Answer(s): (a) 10.40 a.m.; (b) 1 h