City T and City U is 525 km apart. Vincent left City T for City U at 7.00 a.m. travelling at an average speed of 75 km/h. Michael left City T later than Vincent and caught up with him at 9.00 a.m. Michael was travelling at a speed of 100 km/h.
- At what time did Michael leave City T?
- How much later did Vincent arrive in City U than Michael? Express your answer in h as a fraction or mixed number.
(a)
From 7.00 a.m. to 9.00 a.m. = 2 h
Distance that Vincent covered when Michael caught up with Vincent
= 2 x 75
= 150 km
Time that Michael took to travel 150 km
= 150 ÷ 100
= 1
12 h
1 h = 60 min
12 h =
12 x 60 = 30 min
1
12 h = 1 h 30 min
Time that Michael left City T:
1 h 30 min before 9.00 a.m. = 7.30 a.m.
(b)
Remaining distance that they had to cover to reach City U
= 525 - 150
= 375 km
Duration that Michael had to travel before reaching City U
= 375 ÷ 100
= 3
34 h
Duration that Vincent had to travel before reaching City U
= 375 ÷ 75
= 5 h
Duration that Vincent took to arrive later than Michael in City U
= 5 - 3
34= 1
14 h
Answer(s): (a) 7.30 a.m.; (b) 1
14 h
