City K and City L is 360 km apart. Gabriel left City K for City L at 9.00 a.m. travelling at an average speed of 60 km/h. Simon left City K later than Gabriel and caught up with him at 1.00 p.m. Simon was travelling at a speed of 90 km/h.
- At what time did Simon leave City K?
- How much later did Gabriel arrive in City L than Simon? Express your answer in h as a fraction or mixed number.
(a)
From 9.00 a.m. to 1.00 p.m. = 4 h
Distance that Gabriel covered when Simon caught up with Gabriel
= 4 x 60
= 240 km
Time that Simon took to travel 240 km
= 240 ÷ 90
= 2
23 h
1 h = 60 min
23 h =
23 x 60 = 40 min
2
23 h = 2 h 40 min
Time that Simon left City K:
2 h 40 min before 1.00 p.m. = 10.20 a.m.
(b)
Remaining distance that they had to cover to reach City L
= 360 - 240
= 120 km
Duration that Simon had to travel before reaching City L
= 120 ÷ 90
= 1
13 h
Duration that Gabriel had to travel before reaching City L
= 120 ÷ 60
= 2 h
Duration that Gabriel took to arrive later than Simon in City L
= 2 - 1
13=
23 h
Answer(s): (a) 10.20 a.m.; (b)
23 h