City A and City B is 444 km apart. Simon left City A for City B at 10.00 a.m. travelling at an average speed of 74 km/h. Mark left City A later than Simon and caught up with him at 12.00 p.m. Mark was travelling at a speed of 111 km/h.

1. At what time did Mark leave City A?
2. How much later did Simon arrive in City B than Mark? Express your answer in h as a fraction or mixed number.

(a)
From 10.00 a.m. to 12.00 p.m. = 2 h

Distance that Simon covered when Mark caught up with Simon
= 2 x 74
= 148 km

Time that Mark took to travel 148 km
= 148 ÷ 111
= 1¹₃ h

1 h = 60 min
¹₃ h = ¹₃ x 60 = 20 min
1¹₃ h = 1 h 20 min

Time that Mark left City A:
1 h 20 min before 12.00 p.m. = 10.40 a.m.

(b)
Remaining distance that they had to cover to reach City B
= 444 - 148
= 296 km

Duration that Mark had to travel before reaching City B
= 296 ÷ 111
= 2²₃ h

Duration that Simon had to travel before reaching City B
= 296 ÷ 74
= 4 h

Duration that Simon took to arrive later than Mark in City B
= 4 - 2²₃
= 1¹₃ h

Answer(s): (a) 10.40 a.m.; (b) 1¹₃ h